class 8: maths: Indices and Cube root:Practice Set:3.1
1. Express the following numbers in index form.
(1) Fifth root of 13
(2) Sixth root of 9
(3) Square root of 256
(4) Cube root of 17
(5) Eighth root of 100
(6) Seventh root of 30
ANSWER :
i.
ii.
iii.
iv.
v.
vi.
2. Write in the form ‘nth root of a’ in each of the following numbers.
i.
ii.
iii.
iv.
v.
vi.
ANSWER :
i. Fourth root of 81.
ii. Square root of 49.
iii. Fifth root of 15.
iv. Ninth root of 512.
v. Nineteenth root of 100.
vi. Seventh root of 6.
Extra Questions and Activities
Question 1.
Using laws of indices, write proper numbers in the following boxes. (Textbook pg, no. 14)
i.
ii.
iii.
iv.
v.
vi.
vii.
viii.
ix.
Solution:
i.
ii.
iii.
iv.
v.
vi.
vii.
viii.
ix.
class 8: maths : Indices and Cube root :Practice Set :3.2
Practice Set :3.2
1. Complete the following table.
S.No. | Number | Power of the root | Root of the power |
1. | Cube of square root of 225 | Square root of cube of 225 | |
2. | |||
3. | |||
4. | |||
5. |
ANSWER :
S.No. | Number | Power of the root | Root of the power |
1. | Cube of square root of 225 | Square root of cube of 225 | |
2. | 4th power of 5th root of 45 | 5th root of 4th power of 45 | |
3. | 6th power of 7th root of 81 | 7th root of 6th power of 81 | |
4. | 4th power of 10th root of 100 | 10th root of 4th power of 100 | |
5. | Cube of 7th root of 21 | 7th root of cube of 21 |
ii.
iii.
iv.
class 8: maths : Indices and Cube root :Practice Set :3.3
Practice Set :3.3
1. Find the cube roots of the following numbers.
(1) 8000
(2) 729
(3) 343
(4) -512
(5) -2744
(6) 32768
ANSWER :
i. 8000
= 2 × 2 × 2 × 10 × 10 × 10
= (2 × 10) × (2 × 10) × (2 × 10)
= (2 × 10)³
= 20³
ii. 729
= (3 × 3) × (3 × 3) × (3 × 3)
= (3 × 3)³
= 9³
iii. 343
= 7 × 7 × 7
= 7³
iv. -512
= 2 × 2 × 2 × 4 × 4 × 4
= (2 × 4) × (2 × 4) × (2 × 4)
= (2 × 4)³
= 8³
∴ – 512 = (- 8) × (- 8) × (- 8)
= (-8)³
v. -2744
= 2 × 2 × 2 × 7 × 7 × 7
= (2 × 7) × (2 × 7) × (2 × 7)
= (2 × 7)³
= 14³
∴ -2744 = (-14) × (-14) × (-14)
= (-14)³
vi. 32768
= 2 × 2 × 2 × 4 × 4 × 4 × 4 × 4 × 4
= (2 × 4 × 4) × (2 × 4 × 4) × (2 × 4 × 4)
= (2 × 4 × 4)³
= 32³
2 .Simplify:
i.
ii.
iii. If
ANSWER :
(2) 1654−−√3=2×2×2×22×3×3×3−−−−−−−√3=2×2×23×3×3−−−−−√3=2333−−√3=(23)3−−−−√3 [ambm=(ab)m]=23
(3) It is given that,
Chapter 3 : Indices and Cube root